SOLUTION OF QUADRATIC EQUATIONS BY FACTORIZATION EXPLAINED WITH
EXAMPLES IN URDU/HINDI 10TH CLASS MATHEMATICS
·
SOLUTION OF QUADRATIC
EQUATIONS BY FACTORIZATION:
In this method here are the few steps to follow:
i)
Write the quadratic equation in the
standard form as
ax2 + bx + c = 0
ii)
Now multiply
‘a’ and ‘c’ as ‘ac’.
iii)
Factorize the
obtained product ‘ac’.
iv)
Take a pair of those
digits from factorization of ‘ac’ which add ups to form ‘bx’ and multiply to
form ‘ac’.
v)
Take commons
from the obtained equation.
vi)
Again take
commons and keep possibly one relation equal to zero.
vii)
Two
possibilities of variable to keep equal to zero.
viii)
Keep those
relations twice equal to zero and find values of variable ‘x’.
·
Example: Solve the quadratic equation by
factorization.
3x2
– 6x = x + 20
The standard form of equation is 3x2 – 7x – 20 = 0
Here a = 3, b = -7, c = -20 and
‘ac’ = 3 x (-20) = -60
Possible pairs of -60 are; -30 x 2 , -15 x 4 , -12 x 5 , -10 x 6 , -20 x 3 which if multiply give -60
Nothing of these pairs by combining form -7x
but the pair -12x + 5x.
Therefore the equation can be written as
3x2
-12x + 5x -20 = 0
Taking common as, 3x (x – 4) + 5 (x – 4) = 0
Again taking common; (x – 4) (3x + 5) = 0
Now there are two possibilities, either x – 4
= 0 or 3x + 5 = 0 because both are multiples of each other.
If x – 4 = 0 then
x = 4
And if 3x
+ 5 = 0 then 3x = -5
& x = -5/3
Therefore the roots of quadratic equation 3x2 – 7x -20 = 0 are ‘-5’ and
‘-5/3’.
The solution set is {-5, -5/3}.
For understanding more comprehensively,
watch the video from start to end and full procedure of factoring the Quadratic
Equation has been explained with many examples.
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